3x^2+4y^2=121

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Solution for 3x^2+4y^2=121 equation:


Simplifying
3x2 + 4y2 = 121

Solving
3x2 + 4y2 = 121

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4y2' to each side of the equation.
3x2 + 4y2 + -4y2 = 121 + -4y2

Combine like terms: 4y2 + -4y2 = 0
3x2 + 0 = 121 + -4y2
3x2 = 121 + -4y2

Divide each side by '3'.
x2 = 40.33333333 + -1.333333333y2

Simplifying
x2 = 40.33333333 + -1.333333333y2

Reorder the terms:
-40.33333333 + x2 + 1.333333333y2 = 40.33333333 + -1.333333333y2 + -40.33333333 + 1.333333333y2

Reorder the terms:
-40.33333333 + x2 + 1.333333333y2 = 40.33333333 + -40.33333333 + -1.333333333y2 + 1.333333333y2

Combine like terms: 40.33333333 + -40.33333333 = 0.00000000
-40.33333333 + x2 + 1.333333333y2 = 0.00000000 + -1.333333333y2 + 1.333333333y2
-40.33333333 + x2 + 1.333333333y2 = -1.333333333y2 + 1.333333333y2

Combine like terms: -1.333333333y2 + 1.333333333y2 = 0.000000000
-40.33333333 + x2 + 1.333333333y2 = 0.000000000

The solution to this equation could not be determined.

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